-(4/(x^2-3x))

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Solution for -(4/(x^2-3x)) equation: 


D( x )

x^2-(3*x) = 0

x^2-(3*x) = 0

x^2-(3*x) = 0

x^2-3*x = 0

x^2-3*x = 0

DELTA = (-3)^2-(0*1*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)+3)/(1*2) or x = (3-9^(1/2))/(1*2)

x = 3 or x = 0

x in (-oo:0) U (0:3) U (3:+oo)

-(4/(x^2-(3*x))) = 0

-(4/(x^2-3*x)) = 0

(-1*4)/(x^2-3*x) = 0

x^2-3*x = 0

x*(x-3) = 0

x-3 = 0 // + 3

x = 3

x*(x-3) = 0

(-1*4)/(x*(x-3)) = 0

( -1 )

-1 = 0

x belongs to the empty set

( 4 )

4 = 0

x belongs to the empty set

x belongs to the empty set

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